5y^2-22y+24=0

Solution for 5y^2-22y+24=0 equation:

5y^2-22y+24=0

a = 5; b = -22; c = +24;
Δ = b2-4ac
Δ = -222-4·5·24
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2}{2*5}=\frac{20}{10}
=2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2}{2*5}=\frac{24}{10}
=2+2/5
$